The problem is to simplify the expression $\sqrt{(3-\pi)^2}$.

AlgebraSimplificationAbsolute ValueSquare RootReal Numbers
2025/3/11

1. Problem Description

The problem is to simplify the expression (3π)2\sqrt{(3-\pi)^2}.

2. Solution Steps

We need to simplify the expression (3π)2\sqrt{(3-\pi)^2}. Recall the following property:
x2=x\sqrt{x^2} = |x|
Therefore, (3π)2=3π\sqrt{(3-\pi)^2} = |3-\pi|.
Since π3.14159\pi \approx 3.14159, we have that 3π<03 - \pi < 0. The absolute value of a negative number is its negation.
Therefore, 3π=(3π)=π3|3 - \pi| = -(3-\pi) = \pi - 3.

3. Final Answer

π3\pi - 3

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