Simplify the expression $\sqrt[3]{216x^4y^3}$.

AlgebraSimplificationRadicalsExponents
2025/4/8

1. Problem Description

Simplify the expression 216x4y33\sqrt[3]{216x^4y^3}.

2. Solution Steps

We are asked to simplify 216x4y33\sqrt[3]{216x^4y^3}. We can rewrite the expression as follows:
216x4y33=2163x43y33\sqrt[3]{216x^4y^3} = \sqrt[3]{216} \cdot \sqrt[3]{x^4} \cdot \sqrt[3]{y^3}
First, let's find the cube root of 216:
216=666=63216 = 6 \cdot 6 \cdot 6 = 6^3
2163=633=6\sqrt[3]{216} = \sqrt[3]{6^3} = 6
Next, let's simplify x43\sqrt[3]{x^4}. We can rewrite x4x^4 as x3xx^3 \cdot x.
x43=x3x3=x33x3=xx3\sqrt[3]{x^4} = \sqrt[3]{x^3 \cdot x} = \sqrt[3]{x^3} \cdot \sqrt[3]{x} = x\sqrt[3]{x}
Finally, let's simplify y33\sqrt[3]{y^3}.
y33=y\sqrt[3]{y^3} = y
Putting it all together:
216x4y33=6xx3y=6xyx3\sqrt[3]{216x^4y^3} = 6 \cdot x\sqrt[3]{x} \cdot y = 6xy\sqrt[3]{x}

3. Final Answer

The final answer is 6xyx36xy\sqrt[3]{x}

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