The problem is to find the second derivative of the function $y = 20x^3$. We need to find $y''$.

AnalysisDifferentiationPower RuleSecond DerivativeCalculus
2025/4/24

1. Problem Description

The problem is to find the second derivative of the function y=20x3y = 20x^3. We need to find yy''.

2. Solution Steps

First, we find the first derivative, yy', with respect to xx.
The power rule for differentiation states that if y=axny = ax^n, then dydx=naxn1\frac{dy}{dx} = nax^{n-1}.
Applying the power rule:
y=20x3y = 20x^3
y=ddx(20x3)=320x31=60x2y' = \frac{d}{dx}(20x^3) = 3 \cdot 20x^{3-1} = 60x^2
Now, we find the second derivative, yy'', which is the derivative of yy' with respect to xx.
y=60x2y' = 60x^2
y=ddx(60x2)=260x21=120xy'' = \frac{d}{dx}(60x^2) = 2 \cdot 60x^{2-1} = 120x

3. Final Answer

The second derivative is y=120xy'' = 120x.

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