The problem asks to find the product of $(8x-8)^2$.AlgebraAlgebraic ExpansionQuadratic ExpressionsSimplification2025/3/171. Problem DescriptionThe problem asks to find the product of (8x−8)2(8x-8)^2(8x−8)2.2. Solution StepsWe need to expand (8x−8)2(8x-8)^2(8x−8)2.We can use the formula (a−b)2=a2−2ab+b2(a-b)^2 = a^2 - 2ab + b^2(a−b)2=a2−2ab+b2.In our case, a=8xa=8xa=8x and b=8b=8b=8.So we have:(8x−8)2=(8x)2−2(8x)(8)+(8)2(8x-8)^2 = (8x)^2 - 2(8x)(8) + (8)^2(8x−8)2=(8x)2−2(8x)(8)+(8)2(8x)2=64x2(8x)^2 = 64x^2(8x)2=64x22(8x)(8)=128x2(8x)(8) = 128x2(8x)(8)=128x(8)2=64(8)^2 = 64(8)2=64Therefore, (8x−8)2=64x2−128x+64(8x-8)^2 = 64x^2 - 128x + 64(8x−8)2=64x2−128x+64.3. Final Answer64x2−128x+6464x^2 - 128x + 6464x2−128x+64