We are asked to find the equation of a line with slope $m = \frac{3}{5}$ that passes through the point $(5, -2)$.

AlgebraLinear EquationsSlope-intercept formPoint-slope form
2025/3/19

1. Problem Description

We are asked to find the equation of a line with slope m=35m = \frac{3}{5} that passes through the point (5,2)(5, -2).

2. Solution Steps

We can use the point-slope form of a line, which is:
yy1=m(xx1)y - y_1 = m(x - x_1)
where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line.
In our case, m=35m = \frac{3}{5} and (x1,y1)=(5,2)(x_1, y_1) = (5, -2). Plugging these values into the point-slope form, we get:
y(2)=35(x5)y - (-2) = \frac{3}{5}(x - 5)
y+2=35x35(5)y + 2 = \frac{3}{5}x - \frac{3}{5}(5)
y+2=35x3y + 2 = \frac{3}{5}x - 3
Now, we can solve for yy to get the slope-intercept form:
y=35x32y = \frac{3}{5}x - 3 - 2
y=35x5y = \frac{3}{5}x - 5

3. Final Answer

The equation of the line is y=35x5y = \frac{3}{5}x - 5.

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