The problem asks us to expand the expression $(2x + y - 3z)^2$.AlgebraAlgebraic ExpansionPolynomialsMultivariable Expressions2025/5/101. Problem DescriptionThe problem asks us to expand the expression (2x+y−3z)2(2x + y - 3z)^2(2x+y−3z)2.2. Solution StepsWe can use the formula (a+b+c)2=a2+b2+c2+2ab+2bc+2ca(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca(a+b+c)2=a2+b2+c2+2ab+2bc+2ca.In our case, a=2xa = 2xa=2x, b=yb = yb=y, and c=−3zc = -3zc=−3z.Applying the formula, we get:(2x+y−3z)2=(2x)2+(y)2+(−3z)2+2(2x)(y)+2(y)(−3z)+2(−3z)(2x)(2x + y - 3z)^2 = (2x)^2 + (y)^2 + (-3z)^2 + 2(2x)(y) + 2(y)(-3z) + 2(-3z)(2x)(2x+y−3z)2=(2x)2+(y)2+(−3z)2+2(2x)(y)+2(y)(−3z)+2(−3z)(2x)=4x2+y2+9z2+4xy−6yz−12zx= 4x^2 + y^2 + 9z^2 + 4xy - 6yz - 12zx=4x2+y2+9z2+4xy−6yz−12zxTherefore, (2x+y−3z)2=4x2+y2+9z2+4xy−6yz−12zx(2x + y - 3z)^2 = 4x^2 + y^2 + 9z^2 + 4xy - 6yz - 12zx(2x+y−3z)2=4x2+y2+9z2+4xy−6yz−12zx.3. Final Answer4x2+y2+9z2+4xy−6yz−12zx4x^2 + y^2 + 9z^2 + 4xy - 6yz - 12zx4x2+y2+9z2+4xy−6yz−12zx