The problem asks us to expand the expression $(a - b + c)^2$.

AlgebraAlgebraic ExpansionPolynomials
2025/5/10

1. Problem Description

The problem asks us to expand the expression (ab+c)2(a - b + c)^2.

2. Solution Steps

We can expand the expression (ab+c)2(a - b + c)^2 by multiplying it by itself:
(ab+c)2=(ab+c)(ab+c)(a - b + c)^2 = (a - b + c)(a - b + c)
Now, we distribute each term in the first parentheses to each term in the second parentheses:
=a(ab+c)b(ab+c)+c(ab+c)= a(a - b + c) - b(a - b + c) + c(a - b + c)
=a2ab+acba+b2bc+cacb+c2= a^2 - ab + ac - ba + b^2 - bc + ca - cb + c^2
Combine like terms:
=a2+b2+c2abba+ac+cabccb= a^2 + b^2 + c^2 - ab - ba + ac + ca - bc - cb
Since ab=baab = ba, ac=caac = ca, and bc=cbbc = cb, we can simplify further:
=a2+b2+c22ab+2ac2bc= a^2 + b^2 + c^2 - 2ab + 2ac - 2bc
Alternatively, we can use the formula (x+y+z)2=x2+y2+z2+2xy+2xz+2yz(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2xz + 2yz.
In our case, x=ax = a, y=by = -b, and z=cz = c.
So, (ab+c)2=a2+(b)2+c2+2(a)(b)+2(a)(c)+2(b)(c)(a - b + c)^2 = a^2 + (-b)^2 + c^2 + 2(a)(-b) + 2(a)(c) + 2(-b)(c)
=a2+b2+c22ab+2ac2bc= a^2 + b^2 + c^2 - 2ab + 2ac - 2bc

3. Final Answer

The expansion of (ab+c)2(a - b + c)^2 is a2+b2+c22ab+2ac2bca^2 + b^2 + c^2 - 2ab + 2ac - 2bc.