We are asked to solve the equation $\ln(x) - \ln(9) = 10$ for $x$ and give the answer correct to 3 decimal places.

AlgebraLogarithmsExponential FunctionsSolving Equations
2025/3/8

1. Problem Description

We are asked to solve the equation ln(x)ln(9)=10\ln(x) - \ln(9) = 10 for xx and give the answer correct to 3 decimal places.

2. Solution Steps

First, we use the property of logarithms that ln(a)ln(b)=ln(ab)\ln(a) - \ln(b) = \ln(\frac{a}{b}) to rewrite the equation as:
ln(x9)=10\ln(\frac{x}{9}) = 10
Next, we exponentiate both sides of the equation using the base ee to remove the natural logarithm:
eln(x9)=e10e^{\ln(\frac{x}{9})} = e^{10}
x9=e10\frac{x}{9} = e^{10}
Now, we solve for xx by multiplying both sides by 9:
x=9e10x = 9e^{10}
Finally, we approximate the value of xx to 3 decimal places.
x9×22026.46579x \approx 9 \times 22026.46579
x198238.19211x \approx 198238.19211
Rounding to three decimal places, we get x198238.192x \approx 198238.192.

3. Final Answer

x=9e10198238.192x = 9e^{10} \approx 198238.192

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