The problem asks to estimate the instantaneous rate of change of the function $f(x) = x^3 + 4x^2 - 11x - 30$ at $x = 7$. This is equivalent to finding the derivative of the function at $x = 7$, which is $f'(7)$.

AnalysisCalculusDerivativesInstantaneous Rate of ChangePower RulePolynomials
2025/3/26

1. Problem Description

The problem asks to estimate the instantaneous rate of change of the function f(x)=x3+4x211x30f(x) = x^3 + 4x^2 - 11x - 30 at x=7x = 7. This is equivalent to finding the derivative of the function at x=7x = 7, which is f(7)f'(7).

2. Solution Steps

First, find the derivative of the function f(x)f(x) with respect to xx:
f(x)=ddx(x3+4x211x30)f'(x) = \frac{d}{dx} (x^3 + 4x^2 - 11x - 30)
Apply the power rule to each term:
ddx(xn)=nxn1\frac{d}{dx}(x^n) = nx^{n-1}
Therefore,
f(x)=3x2+8x11f'(x) = 3x^2 + 8x - 11
Now, evaluate the derivative at x=7x = 7:
f(7)=3(7)2+8(7)11f'(7) = 3(7)^2 + 8(7) - 11
f(7)=3(49)+5611f'(7) = 3(49) + 56 - 11
f(7)=147+5611f'(7) = 147 + 56 - 11
f(7)=20311f'(7) = 203 - 11
f(7)=192f'(7) = 192

3. Final Answer

The instantaneous rate of change of the function f(x)f(x) at x=7x=7 is 192.

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