与えられた分数に関する計算問題（足し算、引き算、掛け算、割り算）の穴埋め問題です。 (1) $\frac{3}{4} + \square = \frac{11}{12}$ (2) $\square - \frac{1}{6} = \frac{7}{8}$ (3) $\square \times 5 = 2\frac{11}{12}$ (4) $1\frac{5}{7} \div \square = 4$ (5) $2\frac{1}{4} \times \square = 3\frac{1}{30}$ (6) $\frac{33}{35} - \square = \frac{9}{14}$

1. 問題の内容

与えられた分数に関する計算問題（足し算、引き算、掛け算、割り算）の穴埋め問題です。

(1) $\frac{3}{4} + \square = \frac{11}{12}$

(2) $\square - \frac{1}{6} = \frac{7}{8}$

(3) $\square \times 5 = 2\frac{11}{12}$

(4) $1\frac{5}{7} \div \square = 4$

(5) $2\frac{1}{4} \times \square = 3\frac{1}{30}$

(6) $\frac{33}{35} - \square = \frac{9}{14}$

2. 解き方の手順

(1) $\frac{3}{4} + \square = \frac{11}{12}$ を解く。

$\square = \frac{11}{12} - \frac{3}{4} = \frac{11}{12} - \frac{9}{12} = \frac{2}{12} = \frac{1}{6}$

(2) $\square - \frac{1}{6} = \frac{7}{8}$ を解く。

$\square = \frac{7}{8} + \frac{1}{6} = \frac{21}{24} + \frac{4}{24} = \frac{25}{24}$

(3) $\square \times 5 = 2\frac{11}{12}$ を解く。

$2\frac{11}{12} = \frac{2 \times 12 + 11}{12} = \frac{24 + 11}{12} = \frac{35}{12}$

$\square = \frac{35}{12} \div 5 = \frac{35}{12} \times \frac{1}{5} = \frac{7}{12}$

(4) $1\frac{5}{7} \div \square = 4$ を解く。

$1\frac{5}{7} = \frac{1 \times 7 + 5}{7} = \frac{12}{7}$

$\frac{12}{7} \div \square = 4$

$\square = \frac{12}{7} \div 4 = \frac{12}{7} \times \frac{1}{4} = \frac{3}{7}$

(5) $2\frac{1}{4} \times \square = 3\frac{1}{30}$ を解く。

$2\frac{1}{4} = \frac{2 \times 4 + 1}{4} = \frac{9}{4}$

$3\frac{1}{30} = \frac{3 \times 30 + 1}{30} = \frac{91}{30}$

$\frac{9}{4} \times \square = \frac{91}{30}$

$\square = \frac{91}{30} \div \frac{9}{4} = \frac{91}{30} \times \frac{4}{9} = \frac{91 \times 2}{15 \times 9} = \frac{182}{135}$

(6) $\frac{33}{35} - \square = \frac{9}{14}$ を解く。

$\square = \frac{33}{35} - \frac{9}{14} = \frac{33 \times 2}{35 \times 2} - \frac{9 \times 5}{14 \times 5} = \frac{66}{70} - \frac{45}{70} = \frac{21}{70} = \frac{3}{10}$

3. 最終的な答え

(1) $\frac{1}{6}$

(2) $\frac{25}{24}$

(3) $\frac{7}{12}$

(4) $\frac{3}{7}$

(5) $\frac{182}{135}$

(6) $\frac{3}{10}$