We are asked to find the gradient $\nabla f$ of the function $f(x, y, z) = x^2y + y^2z + z^2x$.

AnalysisMultivariable CalculusGradientPartial DerivativesVector Calculus
2025/4/30

1. Problem Description

We are asked to find the gradient f\nabla f of the function f(x,y,z)=x2y+y2z+z2xf(x, y, z) = x^2y + y^2z + z^2x.

2. Solution Steps

The gradient f\nabla f of a scalar function f(x,y,z)f(x, y, z) is a vector given by:
f=(fx,fy,fz)\nabla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z} \right)
We need to compute the partial derivatives of f(x,y,z)=x2y+y2z+z2xf(x, y, z) = x^2y + y^2z + z^2x with respect to xx, yy, and zz.
fx=x(x2y+y2z+z2x)=2xy+0+z2=2xy+z2\frac{\partial f}{\partial x} = \frac{\partial}{\partial x} (x^2y + y^2z + z^2x) = 2xy + 0 + z^2 = 2xy + z^2
fy=y(x2y+y2z+z2x)=x2+2yz+0=x2+2yz\frac{\partial f}{\partial y} = \frac{\partial}{\partial y} (x^2y + y^2z + z^2x) = x^2 + 2yz + 0 = x^2 + 2yz
fz=z(x2y+y2z+z2x)=0+y2+2zx=y2+2zx\frac{\partial f}{\partial z} = \frac{\partial}{\partial z} (x^2y + y^2z + z^2x) = 0 + y^2 + 2zx = y^2 + 2zx
Therefore, the gradient is:
f=(2xy+z2,x2+2yz,y2+2zx)\nabla f = (2xy + z^2, x^2 + 2yz, y^2 + 2zx)

3. Final Answer

f=(2xy+z2,x2+2yz,y2+2zx)\nabla f = (2xy + z^2, x^2 + 2yz, y^2 + 2zx)

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