循環小数 $0.31\dot{2} - 0.1\dot{3}2\dot{4}$ を計算します。算数循環小数分数計算2025/5/241. 問題の内容循環小数 0.312˙−0.13˙24˙0.31\dot{2} - 0.1\dot{3}2\dot{4}0.312˙−0.13˙24˙ を計算します。2. 解き方の手順まず、それぞれの循環小数を分数で表します。0.312˙=0.312222...0.31\dot{2} = 0.312222...0.312˙=0.312222...x=0.312222...x = 0.312222...x=0.312222... とおくと、100x=31.2222...100x = 31.2222...100x=31.2222...1000x=312.2222...1000x = 312.2222...1000x=312.2222...1000x−100x=312.2222...−31.2222...1000x - 100x = 312.2222... - 31.2222...1000x−100x=312.2222...−31.2222...900x=281900x = 281900x=281x=281900x = \frac{281}{900}x=900281次に、0.13˙24˙=0.1324324324...0.1\dot{3}2\dot{4} = 0.1324324324...0.13˙24˙=0.1324324324...y=0.1324324324...y = 0.1324324324...y=0.1324324324... とおくと、10y=1.324324324...10y = 1.324324324...10y=1.324324324...10000y=1324.324324324...10000y = 1324.324324324...10000y=1324.324324324...10000y−10y=1324.324324...−1.324324...10000y - 10y = 1324.324324... - 1.324324...10000y−10y=1324.324324...−1.324324...9990y=13239990y = 13239990y=1323y=13239990=49370y = \frac{1323}{9990} = \frac{49}{370}y=99901323=37049したがって、0.312˙−0.13˙24˙=281900−49370=281×37900×37−49×90370×90=1039733300−441033300=10397−441033300=5987333000.31\dot{2} - 0.1\dot{3}2\dot{4} = \frac{281}{900} - \frac{49}{370} = \frac{281 \times 37}{900 \times 37} - \frac{49 \times 90}{370 \times 90} = \frac{10397}{33300} - \frac{4410}{33300} = \frac{10397 - 4410}{33300} = \frac{5987}{33300}0.312˙−0.13˙24˙=900281−37049=900×37281×37−370×9049×90=3330010397−333004410=3330010397−4410=3330059873. 最終的な答え598733300\frac{5987}{33300}333005987