与えられた9つの計算問題を解く。代数学式の計算分配法則分数2025/7/21. 問題の内容与えられた9つの計算問題を解く。2. 解き方の手順(1) −2x×9=−18x-2x \times 9 = -18x−2x×9=−18x(2) 6a÷(−8)=6a−8=−34a6a \div (-8) = \frac{6a}{-8} = -\frac{3}{4}a6a÷(−8)=−86a=−43a(3) −23x÷(−415)=−23x×(−154)=2×153×4x=3012x=52x-\frac{2}{3}x \div \left(-\frac{4}{15}\right) = -\frac{2}{3}x \times \left(-\frac{15}{4}\right) = \frac{2 \times 15}{3 \times 4}x = \frac{30}{12}x = \frac{5}{2}x−32x÷(−154)=−32x×(−415)=3×42×15x=1230x=25x(4) 5(3a−1)=5×3a−5×1=15a−55(3a - 1) = 5 \times 3a - 5 \times 1 = 15a - 55(3a−1)=5×3a−5×1=15a−5(5) (4a−5)×(−6)=4a×(−6)−5×(−6)=−24a+30(4a - 5) \times (-6) = 4a \times (-6) - 5 \times (-6) = -24a + 30(4a−5)×(−6)=4a×(−6)−5×(−6)=−24a+30(6) (8a−20)×34=8a×34−20×34=6a−15(8a - 20) \times \frac{3}{4} = 8a \times \frac{3}{4} - 20 \times \frac{3}{4} = 6a - 15(8a−20)×43=8a×43−20×43=6a−15(7) 12(56x+14)=12×56x+12×14=10x+312\left(\frac{5}{6}x + \frac{1}{4}\right) = 12 \times \frac{5}{6}x + 12 \times \frac{1}{4} = 10x + 312(65x+41)=12×65x+12×41=10x+3(8) (45a−5)÷5=45a5−55=9a−1(45a - 5) \div 5 = \frac{45a}{5} - \frac{5}{5} = 9a - 1(45a−5)÷5=545a−55=9a−1(9) (6−9x)÷(−32)=(6−9x)×(−23)=6×(−23)−9x×(−23)=−4+6x=6x−4(6 - 9x) \div \left(-\frac{3}{2}\right) = (6 - 9x) \times \left(-\frac{2}{3}\right) = 6 \times \left(-\frac{2}{3}\right) - 9x \times \left(-\frac{2}{3}\right) = -4 + 6x = 6x - 4(6−9x)÷(−23)=(6−9x)×(−32)=6×(−32)−9x×(−32)=−4+6x=6x−43. 最終的な答え(1) −18x-18x−18x(2) −34a-\frac{3}{4}a−43a(3) 52x\frac{5}{2}x25x(4) 15a−515a - 515a−5(5) −24a+30-24a + 30−24a+30(6) 6a−156a - 156a−15(7) 10x+310x + 310x+3(8) 9a−19a - 19a−1(9) 6x−46x - 46x−4