We need to find the value of $\theta$ given the equation $\cos{\theta} = \frac{0}{\sqrt{2} \times 3}$.

TrigonometryTrigonometryCosineAngleEquation Solving
2025/4/5

1. Problem Description

We need to find the value of θ\theta given the equation cosθ=02×3\cos{\theta} = \frac{0}{\sqrt{2} \times 3}.

2. Solution Steps

First, simplify the right-hand side of the equation:
cosθ=02×3=032=0\cos{\theta} = \frac{0}{\sqrt{2} \times 3} = \frac{0}{3\sqrt{2}} = 0
Now, we need to find the angle θ\theta such that cosθ=0\cos{\theta} = 0.
We know that cos(π2)=0\cos(\frac{\pi}{2}) = 0 and cos(3π2)=0\cos(\frac{3\pi}{2}) = 0. In general, cos(θ)=0\cos(\theta) = 0 when θ=(2n+1)π2\theta = \frac{(2n+1)\pi}{2}, where nn is an integer.
Typically, we are interested in the values of θ\theta within the range [0,2π)[0, 2\pi).
So, θ=π2\theta = \frac{\pi}{2} and θ=3π2\theta = \frac{3\pi}{2} are solutions.
If we want the general solution, then θ=π2+nπ\theta = \frac{\pi}{2} + n\pi, where nn is an integer.
However, if we are looking for a single value, we can choose the smallest positive value.

3. Final Answer

θ=π2\theta = \frac{\pi}{2}

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