与えられた $x$ の値を式 $2x-1$ に代入して、式の値を求める問題です。代数学式の計算一次式代入2025/8/51. 問題の内容与えられた xxx の値を式 2x−12x-12x−1 に代入して、式の値を求める問題です。2. 解き方の手順xxx の値を 2x−12x-12x−1 に代入し、計算を行います。(1) x=−3x = -3x=−3 のとき:2x−1=2(−3)−1=−6−1=−72x-1 = 2(-3) - 1 = -6 - 1 = -72x−1=2(−3)−1=−6−1=−7(2) x=−2x = -2x=−2 のとき:2x−1=2(−2)−1=−4−1=−52x-1 = 2(-2) - 1 = -4 - 1 = -52x−1=2(−2)−1=−4−1=−5(3) x=−1x = -1x=−1 のとき:2x−1=2(−1)−1=−2−1=−32x-1 = 2(-1) - 1 = -2 - 1 = -32x−1=2(−1)−1=−2−1=−3(4) x=−12x = -\frac{1}{2}x=−21 のとき:2x−1=2(−12)−1=−1−1=−22x-1 = 2(-\frac{1}{2}) - 1 = -1 - 1 = -22x−1=2(−21)−1=−1−1=−2(5) x=0x = 0x=0 のとき:2x−1=2(0)−1=0−1=−12x-1 = 2(0) - 1 = 0 - 1 = -12x−1=2(0)−1=0−1=−1(6) x=12x = \frac{1}{2}x=21 のとき:2x−1=2(12)−1=1−1=02x-1 = 2(\frac{1}{2}) - 1 = 1 - 1 = 02x−1=2(21)−1=1−1=0(7) x=1x = 1x=1 のとき:2x−1=2(1)−1=2−1=12x-1 = 2(1) - 1 = 2 - 1 = 12x−1=2(1)−1=2−1=1(8) x=2x = 2x=2 のとき:2x−1=2(2)−1=4−1=32x-1 = 2(2) - 1 = 4 - 1 = 32x−1=2(2)−1=4−1=33. 最終的な答え(1) -7(2) -5(3) -3(4) -2(5) -1(6) 0(7) 1(8) 3