The problem asks us to evaluate the definite integral $\int (2x+1)^7 dx$.

AnalysisDefinite IntegralIntegrationSubstitutionPower Rule
2025/4/30

1. Problem Description

The problem asks us to evaluate the definite integral (2x+1)7dx\int (2x+1)^7 dx.

2. Solution Steps

We can use the substitution method to solve this integral.
Let u=2x+1u = 2x+1. Then, the derivative of uu with respect to xx is dudx=2\frac{du}{dx} = 2.
So, du=2dxdu = 2dx, and dx=12dudx = \frac{1}{2} du.
Now, we can rewrite the integral in terms of uu:
(2x+1)7dx=u712du=12u7du\int (2x+1)^7 dx = \int u^7 \cdot \frac{1}{2} du = \frac{1}{2} \int u^7 du
Now, we can use the power rule for integration, which states that xndx=xn+1n+1+C\int x^n dx = \frac{x^{n+1}}{n+1} + C, where CC is the constant of integration.
Applying the power rule to our integral, we get:
12u7du=12u7+17+1+C=12u88+C=u816+C\frac{1}{2} \int u^7 du = \frac{1}{2} \cdot \frac{u^{7+1}}{7+1} + C = \frac{1}{2} \cdot \frac{u^8}{8} + C = \frac{u^8}{16} + C
Now, we substitute back u=2x+1u = 2x+1 to express the result in terms of xx:
(2x+1)816+C\frac{(2x+1)^8}{16} + C

3. Final Answer

(2x+1)816+C\frac{(2x+1)^8}{16} + C

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