与えられた方程式を解きます。問題は次の通りです。 (1) $4 + 6x = 13$ (5) $10x + 1 = -5x + 4$ (9) $-2x + 20 = -4x + 8$ (13) $-6 = 4x - 7$ (2) $12x = 9x - 15$ (6) $-18x + 1 = -9x - 14$ (10) $13 + 7x = -5x - 3$ (14) $-3 = 6x - 4$

1. 問題の内容

与えられた方程式を解きます。問題は次の通りです。

(1) $4 + 6x = 13$

(5) $10x + 1 = -5x + 4$

(9) $-2x + 20 = -4x + 8$

(13) $-6 = 4x - 7$

(2) $12x = 9x - 15$

(6) $-18x + 1 = -9x - 14$

(10) $13 + 7x = -5x - 3$

(14) $-3 = 6x - 4$

2. 解き方の手順

(1) $4 + 6x = 13$

$6x = 13 - 4$

$6x = 9$

$x = \frac{9}{6}$

$x = \frac{3}{2}$

(5) $10x + 1 = -5x + 4$

$10x + 5x = 4 - 1$

$15x = 3$

$x = \frac{3}{15}$

$x = \frac{1}{5}$

(9) $-2x + 20 = -4x + 8$

$-2x + 4x = 8 - 20$

$2x = -12$

$x = -6$

(13) $-6 = 4x - 7$

$4x = -6 + 7$

$4x = 1$

$x = \frac{1}{4}$

(2) $12x = 9x - 15$

$12x - 9x = -15$

$3x = -15$

$x = -5$

(6) $-18x + 1 = -9x - 14$

$-18x + 9x = -14 - 1$

$-9x = -15$

$x = \frac{-15}{-9}$

$x = \frac{5}{3}$

(10) $13 + 7x = -5x - 3$

$7x + 5x = -3 - 13$

$12x = -16$

$x = \frac{-16}{12}$

$x = \frac{-4}{3}$

(14) $-3 = 6x - 4$

$6x = -3 + 4$

$6x = 1$

$x = \frac{1}{6}$

3. 最終的な答え

(1) $x = \frac{3}{2}$

(5) $x = \frac{1}{5}$

(9) $x = -6$

(13) $x = \frac{1}{4}$

(2) $x = -5$

(6) $x = \frac{5}{3}$

(10) $x = -\frac{4}{3}$

(14) $x = \frac{1}{6}$