We are given that $\sin A = \frac{3}{8}$ and $\tan A = \frac{3}{4}$. We need to find the value of $\cos A$.

TrigonometryTrigonometrySineCosineTangentTrigonometric Identities
2025/3/27

1. Problem Description

We are given that sinA=38\sin A = \frac{3}{8} and tanA=34\tan A = \frac{3}{4}. We need to find the value of cosA\cos A.

2. Solution Steps

We know that tanA=sinAcosA\tan A = \frac{\sin A}{\cos A}. We can rearrange this formula to solve for cosA\cos A:
cosA=sinAtanA\cos A = \frac{\sin A}{\tan A}
We are given that sinA=38\sin A = \frac{3}{8} and tanA=34\tan A = \frac{3}{4}. Substituting these values into the equation gives:
cosA=3834\cos A = \frac{\frac{3}{8}}{\frac{3}{4}}
cosA=3843\cos A = \frac{3}{8} \cdot \frac{4}{3}
cosA=3483\cos A = \frac{3 \cdot 4}{8 \cdot 3}
cosA=1224\cos A = \frac{12}{24}
cosA=12\cos A = \frac{1}{2}

3. Final Answer

The value of cosA\cos A is 12\frac{1}{2}.
The answer is b. 1/2.

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