$x = -6$ のとき、以下の各式について、その値を求めます。 (1) $3x$ (2) $-3x$ (3) $8x - 5x$ (4) $5x - 8x$ (5) $\frac{x}{2}$ (6) $\frac{1}{2}x$ (7) $\frac{5}{6}x$ (8) $\frac{1}{2}x + \frac{1}{3}x$ (9) $\frac{2}{3}x + \frac{1}{6}x$ (10) $\frac{x}{2} + \frac{x}{6}$

1. 問題の内容

$x = -6$ のとき、以下の各式について、その値を求めます。

(1) $3x$

(2) $-3x$

(3) $8x - 5x$

(4) $5x - 8x$

(5) $\frac{x}{2}$

(6) $\frac{1}{2}x$

(7) $\frac{5}{6}x$

(8) $\frac{1}{2}x + \frac{1}{3}x$

(9) $\frac{2}{3}x + \frac{1}{6}x$

(10) $\frac{x}{2} + \frac{x}{6}$

2. 解き方の手順

各問題について、$x = -6$ を代入して計算を行います。

(1) $3x = 3 \times (-6) = -18$

(2) $-3x = -3 \times (-6) = 18$

(3) $8x - 5x = (8-5)x = 3x = 3 \times (-6) = -18$

(4) $5x - 8x = (5-8)x = -3x = -3 \times (-6) = 18$

(5) $\frac{x}{2} = \frac{-6}{2} = -3$

(6) $\frac{1}{2}x = \frac{1}{2} \times (-6) = -3$

(7) $\frac{5}{6}x = \frac{5}{6} \times (-6) = -5$

(8) $\frac{1}{2}x + \frac{1}{3}x = (\frac{1}{2} + \frac{1}{3})x = (\frac{3}{6} + \frac{2}{6})x = \frac{5}{6}x = \frac{5}{6} \times (-6) = -5$

(9) $\frac{2}{3}x + \frac{1}{6}x = (\frac{2}{3} + \frac{1}{6})x = (\frac{4}{6} + \frac{1}{6})x = \frac{5}{6}x = \frac{5}{6} \times (-6) = -5$

(10) $\frac{x}{2} + \frac{x}{6} = \frac{-6}{2} + \frac{-6}{6} = -3 - 1 = -4$

3. 最終的な答え

(1) $-18$

(2) $18$

(3) $-18$

(4) $18$

(5) $-3$

(6) $-3$

(7) $-5$

(8) $-5$

(9) $-5$

(10) $-4$